Integrand size = 36, antiderivative size = 104 \[ \int \frac {(a+i a \tan (c+d x))^2 (A+B \tan (c+d x))}{\sqrt {\tan (c+d x)}} \, dx=-\frac {4 \sqrt [4]{-1} a^2 (A-i B) \arctan \left ((-1)^{3/4} \sqrt {\tan (c+d x)}\right )}{d}-\frac {2 a^2 (3 A-5 i B) \sqrt {\tan (c+d x)}}{3 d}+\frac {2 i B \sqrt {\tan (c+d x)} \left (a^2+i a^2 \tan (c+d x)\right )}{3 d} \]
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Time = 0.32 (sec) , antiderivative size = 104, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.111, Rules used = {3675, 3673, 3614, 211} \[ \int \frac {(a+i a \tan (c+d x))^2 (A+B \tan (c+d x))}{\sqrt {\tan (c+d x)}} \, dx=-\frac {4 \sqrt [4]{-1} a^2 (A-i B) \arctan \left ((-1)^{3/4} \sqrt {\tan (c+d x)}\right )}{d}-\frac {2 a^2 (3 A-5 i B) \sqrt {\tan (c+d x)}}{3 d}+\frac {2 i B \sqrt {\tan (c+d x)} \left (a^2+i a^2 \tan (c+d x)\right )}{3 d} \]
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Rule 211
Rule 3614
Rule 3673
Rule 3675
Rubi steps \begin{align*} \text {integral}& = \frac {2 i B \sqrt {\tan (c+d x)} \left (a^2+i a^2 \tan (c+d x)\right )}{3 d}+\frac {2}{3} \int \frac {(a+i a \tan (c+d x)) \left (\frac {1}{2} a (3 A-i B)+\frac {1}{2} a (3 i A+5 B) \tan (c+d x)\right )}{\sqrt {\tan (c+d x)}} \, dx \\ & = -\frac {2 a^2 (3 A-5 i B) \sqrt {\tan (c+d x)}}{3 d}+\frac {2 i B \sqrt {\tan (c+d x)} \left (a^2+i a^2 \tan (c+d x)\right )}{3 d}+\frac {2}{3} \int \frac {3 a^2 (A-i B)+3 a^2 (i A+B) \tan (c+d x)}{\sqrt {\tan (c+d x)}} \, dx \\ & = -\frac {2 a^2 (3 A-5 i B) \sqrt {\tan (c+d x)}}{3 d}+\frac {2 i B \sqrt {\tan (c+d x)} \left (a^2+i a^2 \tan (c+d x)\right )}{3 d}+\frac {\left (12 a^4 (A-i B)^2\right ) \text {Subst}\left (\int \frac {1}{3 a^2 (A-i B)-3 a^2 (i A+B) x^2} \, dx,x,\sqrt {\tan (c+d x)}\right )}{d} \\ & = -\frac {4 \sqrt [4]{-1} a^2 (A-i B) \arctan \left ((-1)^{3/4} \sqrt {\tan (c+d x)}\right )}{d}-\frac {2 a^2 (3 A-5 i B) \sqrt {\tan (c+d x)}}{3 d}+\frac {2 i B \sqrt {\tan (c+d x)} \left (a^2+i a^2 \tan (c+d x)\right )}{3 d} \\ \end{align*}
Time = 1.97 (sec) , antiderivative size = 75, normalized size of antiderivative = 0.72 \[ \int \frac {(a+i a \tan (c+d x))^2 (A+B \tan (c+d x))}{\sqrt {\tan (c+d x)}} \, dx=-\frac {2 a^2 \left ((3+3 i) \sqrt {2} (i A+B) \text {arctanh}\left (\frac {(1+i) \sqrt {\tan (c+d x)}}{\sqrt {2}}\right )+\sqrt {\tan (c+d x)} (3 A-6 i B+B \tan (c+d x))\right )}{3 d} \]
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Both result and optimal contain complex but leaf count of result is larger than twice the leaf count of optimal. 228 vs. \(2 (86 ) = 172\).
Time = 0.03 (sec) , antiderivative size = 229, normalized size of antiderivative = 2.20
method | result | size |
derivativedivides | \(\frac {a^{2} \left (-\frac {2 B \left (\tan ^{\frac {3}{2}}\left (d x +c \right )\right )}{3}-2 A \left (\sqrt {\tan }\left (d x +c \right )\right )+4 i B \left (\sqrt {\tan }\left (d x +c \right )\right )+\frac {\left (-2 i B +2 A \right ) \sqrt {2}\, \left (\ln \left (\frac {1+\sqrt {2}\, \left (\sqrt {\tan }\left (d x +c \right )\right )+\tan \left (d x +c \right )}{1-\sqrt {2}\, \left (\sqrt {\tan }\left (d x +c \right )\right )+\tan \left (d x +c \right )}\right )+2 \arctan \left (1+\sqrt {2}\, \left (\sqrt {\tan }\left (d x +c \right )\right )\right )+2 \arctan \left (-1+\sqrt {2}\, \left (\sqrt {\tan }\left (d x +c \right )\right )\right )\right )}{4}+\frac {\left (2 i A +2 B \right ) \sqrt {2}\, \left (\ln \left (\frac {1-\sqrt {2}\, \left (\sqrt {\tan }\left (d x +c \right )\right )+\tan \left (d x +c \right )}{1+\sqrt {2}\, \left (\sqrt {\tan }\left (d x +c \right )\right )+\tan \left (d x +c \right )}\right )+2 \arctan \left (1+\sqrt {2}\, \left (\sqrt {\tan }\left (d x +c \right )\right )\right )+2 \arctan \left (-1+\sqrt {2}\, \left (\sqrt {\tan }\left (d x +c \right )\right )\right )\right )}{4}\right )}{d}\) | \(229\) |
default | \(\frac {a^{2} \left (-\frac {2 B \left (\tan ^{\frac {3}{2}}\left (d x +c \right )\right )}{3}-2 A \left (\sqrt {\tan }\left (d x +c \right )\right )+4 i B \left (\sqrt {\tan }\left (d x +c \right )\right )+\frac {\left (-2 i B +2 A \right ) \sqrt {2}\, \left (\ln \left (\frac {1+\sqrt {2}\, \left (\sqrt {\tan }\left (d x +c \right )\right )+\tan \left (d x +c \right )}{1-\sqrt {2}\, \left (\sqrt {\tan }\left (d x +c \right )\right )+\tan \left (d x +c \right )}\right )+2 \arctan \left (1+\sqrt {2}\, \left (\sqrt {\tan }\left (d x +c \right )\right )\right )+2 \arctan \left (-1+\sqrt {2}\, \left (\sqrt {\tan }\left (d x +c \right )\right )\right )\right )}{4}+\frac {\left (2 i A +2 B \right ) \sqrt {2}\, \left (\ln \left (\frac {1-\sqrt {2}\, \left (\sqrt {\tan }\left (d x +c \right )\right )+\tan \left (d x +c \right )}{1+\sqrt {2}\, \left (\sqrt {\tan }\left (d x +c \right )\right )+\tan \left (d x +c \right )}\right )+2 \arctan \left (1+\sqrt {2}\, \left (\sqrt {\tan }\left (d x +c \right )\right )\right )+2 \arctan \left (-1+\sqrt {2}\, \left (\sqrt {\tan }\left (d x +c \right )\right )\right )\right )}{4}\right )}{d}\) | \(229\) |
parts | \(\frac {\left (2 i A \,a^{2}+B \,a^{2}\right ) \sqrt {2}\, \left (\ln \left (\frac {1-\sqrt {2}\, \left (\sqrt {\tan }\left (d x +c \right )\right )+\tan \left (d x +c \right )}{1+\sqrt {2}\, \left (\sqrt {\tan }\left (d x +c \right )\right )+\tan \left (d x +c \right )}\right )+2 \arctan \left (1+\sqrt {2}\, \left (\sqrt {\tan }\left (d x +c \right )\right )\right )+2 \arctan \left (-1+\sqrt {2}\, \left (\sqrt {\tan }\left (d x +c \right )\right )\right )\right )}{4 d}+\frac {\left (2 i B \,a^{2}-A \,a^{2}\right ) \left (2 \left (\sqrt {\tan }\left (d x +c \right )\right )-\frac {\sqrt {2}\, \left (\ln \left (\frac {1+\sqrt {2}\, \left (\sqrt {\tan }\left (d x +c \right )\right )+\tan \left (d x +c \right )}{1-\sqrt {2}\, \left (\sqrt {\tan }\left (d x +c \right )\right )+\tan \left (d x +c \right )}\right )+2 \arctan \left (1+\sqrt {2}\, \left (\sqrt {\tan }\left (d x +c \right )\right )\right )+2 \arctan \left (-1+\sqrt {2}\, \left (\sqrt {\tan }\left (d x +c \right )\right )\right )\right )}{4}\right )}{d}+\frac {A \,a^{2} \sqrt {2}\, \left (\ln \left (\frac {1+\sqrt {2}\, \left (\sqrt {\tan }\left (d x +c \right )\right )+\tan \left (d x +c \right )}{1-\sqrt {2}\, \left (\sqrt {\tan }\left (d x +c \right )\right )+\tan \left (d x +c \right )}\right )+2 \arctan \left (1+\sqrt {2}\, \left (\sqrt {\tan }\left (d x +c \right )\right )\right )+2 \arctan \left (-1+\sqrt {2}\, \left (\sqrt {\tan }\left (d x +c \right )\right )\right )\right )}{4 d}-\frac {B \,a^{2} \left (\frac {2 \left (\tan ^{\frac {3}{2}}\left (d x +c \right )\right )}{3}-\frac {\sqrt {2}\, \left (\ln \left (\frac {1-\sqrt {2}\, \left (\sqrt {\tan }\left (d x +c \right )\right )+\tan \left (d x +c \right )}{1+\sqrt {2}\, \left (\sqrt {\tan }\left (d x +c \right )\right )+\tan \left (d x +c \right )}\right )+2 \arctan \left (1+\sqrt {2}\, \left (\sqrt {\tan }\left (d x +c \right )\right )\right )+2 \arctan \left (-1+\sqrt {2}\, \left (\sqrt {\tan }\left (d x +c \right )\right )\right )\right )}{4}\right )}{d}\) | \(414\) |
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Both result and optimal contain complex but leaf count of result is larger than twice the leaf count of optimal. 389 vs. \(2 (82) = 164\).
Time = 0.25 (sec) , antiderivative size = 389, normalized size of antiderivative = 3.74 \[ \int \frac {(a+i a \tan (c+d x))^2 (A+B \tan (c+d x))}{\sqrt {\tan (c+d x)}} \, dx=\frac {3 \, \sqrt {-\frac {{\left (i \, A^{2} + 2 \, A B - i \, B^{2}\right )} a^{4}}{d^{2}}} {\left (d e^{\left (2 i \, d x + 2 i \, c\right )} + d\right )} \log \left (-\frac {2 \, {\left ({\left (A - i \, B\right )} a^{2} e^{\left (2 i \, d x + 2 i \, c\right )} + \sqrt {-\frac {{\left (i \, A^{2} + 2 \, A B - i \, B^{2}\right )} a^{4}}{d^{2}}} {\left (i \, d e^{\left (2 i \, d x + 2 i \, c\right )} + i \, d\right )} \sqrt {\frac {-i \, e^{\left (2 i \, d x + 2 i \, c\right )} + i}{e^{\left (2 i \, d x + 2 i \, c\right )} + 1}}\right )} e^{\left (-2 i \, d x - 2 i \, c\right )}}{{\left (-i \, A - B\right )} a^{2}}\right ) - 3 \, \sqrt {-\frac {{\left (i \, A^{2} + 2 \, A B - i \, B^{2}\right )} a^{4}}{d^{2}}} {\left (d e^{\left (2 i \, d x + 2 i \, c\right )} + d\right )} \log \left (-\frac {2 \, {\left ({\left (A - i \, B\right )} a^{2} e^{\left (2 i \, d x + 2 i \, c\right )} + \sqrt {-\frac {{\left (i \, A^{2} + 2 \, A B - i \, B^{2}\right )} a^{4}}{d^{2}}} {\left (-i \, d e^{\left (2 i \, d x + 2 i \, c\right )} - i \, d\right )} \sqrt {\frac {-i \, e^{\left (2 i \, d x + 2 i \, c\right )} + i}{e^{\left (2 i \, d x + 2 i \, c\right )} + 1}}\right )} e^{\left (-2 i \, d x - 2 i \, c\right )}}{{\left (-i \, A - B\right )} a^{2}}\right ) - 2 \, {\left ({\left (3 \, A - 7 i \, B\right )} a^{2} e^{\left (2 i \, d x + 2 i \, c\right )} + {\left (3 \, A - 5 i \, B\right )} a^{2}\right )} \sqrt {\frac {-i \, e^{\left (2 i \, d x + 2 i \, c\right )} + i}{e^{\left (2 i \, d x + 2 i \, c\right )} + 1}}}{3 \, {\left (d e^{\left (2 i \, d x + 2 i \, c\right )} + d\right )}} \]
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\[ \int \frac {(a+i a \tan (c+d x))^2 (A+B \tan (c+d x))}{\sqrt {\tan (c+d x)}} \, dx=- a^{2} \left (\int \left (- \frac {A}{\sqrt {\tan {\left (c + d x \right )}}}\right )\, dx + \int A \tan ^{\frac {3}{2}}{\left (c + d x \right )}\, dx + \int \left (- B \sqrt {\tan {\left (c + d x \right )}}\right )\, dx + \int B \tan ^{\frac {5}{2}}{\left (c + d x \right )}\, dx + \int \left (- 2 i A \sqrt {\tan {\left (c + d x \right )}}\right )\, dx + \int \left (- 2 i B \tan ^{\frac {3}{2}}{\left (c + d x \right )}\right )\, dx\right ) \]
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Both result and optimal contain complex but leaf count of result is larger than twice the leaf count of optimal. 174 vs. \(2 (82) = 164\).
Time = 0.28 (sec) , antiderivative size = 174, normalized size of antiderivative = 1.67 \[ \int \frac {(a+i a \tan (c+d x))^2 (A+B \tan (c+d x))}{\sqrt {\tan (c+d x)}} \, dx=-\frac {4 \, B a^{2} \tan \left (d x + c\right )^{\frac {3}{2}} + 12 \, {\left (A - 2 i \, B\right )} a^{2} \sqrt {\tan \left (d x + c\right )} + 3 \, {\left (2 \, \sqrt {2} {\left (-\left (i + 1\right ) \, A + \left (i - 1\right ) \, B\right )} \arctan \left (\frac {1}{2} \, \sqrt {2} {\left (\sqrt {2} + 2 \, \sqrt {\tan \left (d x + c\right )}\right )}\right ) + 2 \, \sqrt {2} {\left (-\left (i + 1\right ) \, A + \left (i - 1\right ) \, B\right )} \arctan \left (-\frac {1}{2} \, \sqrt {2} {\left (\sqrt {2} - 2 \, \sqrt {\tan \left (d x + c\right )}\right )}\right ) + \sqrt {2} {\left (\left (i - 1\right ) \, A + \left (i + 1\right ) \, B\right )} \log \left (\sqrt {2} \sqrt {\tan \left (d x + c\right )} + \tan \left (d x + c\right ) + 1\right ) - \sqrt {2} {\left (\left (i - 1\right ) \, A + \left (i + 1\right ) \, B\right )} \log \left (-\sqrt {2} \sqrt {\tan \left (d x + c\right )} + \tan \left (d x + c\right ) + 1\right )\right )} a^{2}}{6 \, d} \]
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Time = 0.76 (sec) , antiderivative size = 92, normalized size of antiderivative = 0.88 \[ \int \frac {(a+i a \tan (c+d x))^2 (A+B \tan (c+d x))}{\sqrt {\tan (c+d x)}} \, dx=\frac {\left (2 i - 2\right ) \, \sqrt {2} {\left (-i \, A a^{2} - B a^{2}\right )} \arctan \left (-\left (\frac {1}{2} i - \frac {1}{2}\right ) \, \sqrt {2} \sqrt {\tan \left (d x + c\right )}\right )}{d} - \frac {2 \, {\left (B a^{2} d^{2} \tan \left (d x + c\right )^{\frac {3}{2}} + 3 \, A a^{2} d^{2} \sqrt {\tan \left (d x + c\right )} - 6 i \, B a^{2} d^{2} \sqrt {\tan \left (d x + c\right )}\right )}}{3 \, d^{3}} \]
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Time = 8.85 (sec) , antiderivative size = 221, normalized size of antiderivative = 2.12 \[ \int \frac {(a+i a \tan (c+d x))^2 (A+B \tan (c+d x))}{\sqrt {\tan (c+d x)}} \, dx=-\frac {2\,A\,a^2\,\sqrt {\mathrm {tan}\left (c+d\,x\right )}}{d}+\frac {B\,a^2\,\sqrt {\mathrm {tan}\left (c+d\,x\right )}\,4{}\mathrm {i}}{d}-\frac {2\,B\,a^2\,{\mathrm {tan}\left (c+d\,x\right )}^{3/2}}{3\,d}+\frac {\sqrt {2}\,A\,a^2\,\ln \left (A\,a^2\,d\,4{}\mathrm {i}+\sqrt {2}\,A\,a^2\,d\,\sqrt {\mathrm {tan}\left (c+d\,x\right )}\,\left (-2+2{}\mathrm {i}\right )\right )\,\left (1-\mathrm {i}\right )}{d}-\frac {\sqrt {-4{}\mathrm {i}}\,A\,a^2\,\ln \left (A\,a^2\,d\,4{}\mathrm {i}+2\,\sqrt {-4{}\mathrm {i}}\,A\,a^2\,d\,\sqrt {\mathrm {tan}\left (c+d\,x\right )}\right )}{d}+\frac {\sqrt {2}\,B\,a^2\,\ln \left (4\,B\,a^2\,d+\sqrt {2}\,B\,a^2\,d\,\sqrt {\mathrm {tan}\left (c+d\,x\right )}\,\left (-2-2{}\mathrm {i}\right )\right )\,\left (1+1{}\mathrm {i}\right )}{d}-\frac {\sqrt {4{}\mathrm {i}}\,B\,a^2\,\ln \left (4\,B\,a^2\,d+2\,\sqrt {4{}\mathrm {i}}\,B\,a^2\,d\,\sqrt {\mathrm {tan}\left (c+d\,x\right )}\right )}{d} \]
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